How long will it take for ½ of the original amount of Rubidium-87 to decay? b)How much carbon-14 will be left after 4,000 years? assume the substance has a half-life of 11 years and the initial amount is 126 grams. The rate at which an amount of a radioactive substance decays is modeled by the differential equation d A/dt = k A, where A is the mass in grams, t is the time in years, and k is a constant. a) If a 100-gram sample of the radioactive substance decays to 95 ... If one wishes to accumulate a Php 30,000-fund in 5 years, how much should he deposit now at 18% compounded quarterly? If a bank offers a rate of 4.5% compounded semiannually, how much should you deposit to accumulate Php 50,000 in 15 years 3. How many half-lives have occurred in a sample that contains 50 percent of the original amount of the parent isotope? with solution please Tritium, a radioactive isotope of hydrogen, has a half-life of 12.4 years. a)Write the rule of the function that gives the amount of carbon-14 remaining after x years. If one wishes to accumulate a Php 30,000-fund in 5 years, how much should he deposit now at 18% compounded quarterly? If a bank offers a rate of 4.5% compounded semiannually, how much should you deposit to accumulate Php 50,000 in 15 years 3. Carbon-14 has a half-life of approximately 5,730 years.The half life of a certain radioactive substance is 10 years. A smoke detector contains 0.2 mg of Americium 241 (Am-241), a radioactive element that decays in t years according to the relation m = 0.2(0.5)^(t/432.2). Suppose you have 100 g of radioactive plutonium-239 with a half-life of 24,000 years.How long will it take for 18 gms of the substance to decay to 6 gms? Where m is the mass, in milligrams, remaining after t years. How many grams will remain after (a) 12,000 years (b) 24,000 years (c) 96,000 years? If a sample contains 100 mg, how many mg will remain after 4000 years?If 79% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? An artifact was found and tested for its carbon-14 content.If 81% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? yr An artifact was found and tested for its carbon-14 content.

(Carbon-14 has a half-life of 5,730 years.) thank you An artifact was found and tested for its carbon-14 content.

If 76% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)?

a) Determine the function A’, which represent the rate of decay of the substance. An artifact was found and tested for its carbon-14 content.

If 83% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? An artifact was found and tested for its carbon-14 content. years (b) How long would it take the sample to decay to 10% of its original amount? years An artifact was found and tested for its carbon-14 content. c)After how long will only 2 g of the sample remain? Uranium-238 has half life of 4.51 * 10^9 years Uranium-234 has half life of 2.48 * 10^5 years Thorium-230 has half life of 8.0 * 10^4 years Radium-226 has half life of 1.62 * 10^3 years Lead-210 has half life of 20.4 years.

If 71% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? A sample of a radioactive substance decayed to 93.5% of its original amount after a year. If 88% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? An artifact was found and tested for its carbon-14 content. the amount of carbon-14 in a mammoth's bone is 45% of the amount found in a living organism. The rate constant for the decay of unstable nuclide X... How much of a 1 g sample will remain after 25 years Assuming an element's half-life is 3.6 years.

The half -life of carbon-14 is 5,730 much of an initial amount of this. initial amount of carbon-14, t is the number of. using Carbon-14 dating.

Radioactive Carbon 14 in a dead organism decays according to the. Radioactive carbon-14 dating has. initial amount of carbon-14, t is the number of.